Lounge of Tomorrow

Lounge of Tomorrow (http://74.208.121.111/LoT/index.php)
-   Egg Head (http://74.208.121.111/LoT/forumdisplay.php?f=13)
-   -   Algebraic conumdrum (http://74.208.121.111/LoT/showthread.php?t=1953)

Ghoulish Delight 08-31-2005 08:04 AM

Algebraic conumdrum
 
I've managed to stump myself with a seemingly straight forward problem. Find all valid solutions for a and b in the following expression:

a*b=a

Now, at first the solution is obvious. b=a/a, b=1. So the set of soultions is:

a={all numbers}
b={1}

So far so good. However, a quick, non-algebraic analysis of the expression clearly shows there is another solution set, namely:

a={0}
b={all numbers}

So why can't I get the expression to yield that solution algebraicly? It's obvious looking at it, but I can't find a systematic way of solving the equation to get a=0. What am I missing (and am I going to feel really stupid when someone points it out to me)?

mousepod 08-31-2005 08:22 AM

Algebraically speaking, I'd say that the first solution is the correct one, except in the case where a=0.

0 divided by 0 is considered "undefined" because it poses a conflict between two rules.


All times are GMT -7. The time now is 06:59 PM.

Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.