Thread: Stat 100
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Old 06-04-2008, 09:58 PM   #20
Alex
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Quote:
Originally Posted by BarTopDancer View Post
The mean is 80. The standard deviation is 6. You have to take the Mean ± 2(SD). So 80 ± 2*6 = the answer.
This is correct.

The empirical rule is 68-95-99.7, right? That means that for a normal distribution, one standard deviation will include about 68% of the population. Go out to 2 standard deviations and it will include about 95% of the population. 3 standard deviations takes you up to 99.7% of the population.

So, since the question asks about covering 95% of the results, that would be two standard deviations. That's the reasoning underlying the correct formula you gave. So Answer B (68 to 92) is correct.


Quote:
Part 2.

I have no idea. I am so lost again.
You're correct that 3 standard deviations is ±18 points from the mean (62 to 98). And 5 standard deviations would be ±30 points.

Per the empirical rule, 99.7% of all results will be within just 3 standard deviations of the mean. So we know that only 0.3% of all results will be lower than 62 points or higher than 98 points.

I don't know if it is covered by your textbook but if you extend the empirical rule you get:

1 standard deviation = 68%
2 standard deviation = 97%
3 standard deviation = 99.7%
4 standard deviation = 99.99%
5 standard deviation = 99.9999% of all results

So, since a score of 50 is 5 standard deviations away from the mean, you would expect only 0.0001% of scores to be that far from the mean. Another way of saying that is you'd expect one student out of a million to score that low. Since it is extremely unlikely that a million students are taking the Stats 100 class you would not expect that anybody will score that low (though it remains statistically possible it is statistically improbable).

Last edited by Alex : 06-04-2008 at 10:03 PM.
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