Restaurant Math

Nephythys · 12-19-2008, 06:47 AM

It takes less than a minute. Work this out as you read .

Be sure you don't read the bottom until you've worked it out!

This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to

go out to eat. (more than once but less than 10)

2. Multiply this number by 2 (just to be bold)

3. Add 5

4. Multiply it by 50

5. If you have already had your birthday this year add 1758...

If you haven't, add 1757.

6. Now subtract the four digit year that you were born.

You should have a three digit number

The first digit of this was your original number. ( I. e., How many times
you want to go out to restaurants in a week.)

The next two numbers are

YOUR AGE ! ------ (Oh YES, it is!)

THIS IS THE ONLY YEAR (2008) IT WILL EVER WORK.

Strangler Lewis · 12-19-2008, 06:59 AM

Pedant alert:

It's a fun problem, but it works every year. You just would have added 1757 or 1756 last year and 1756 or 1755 the year before. If you do the algebra where x is the first number you choose, you'll see.

Nephythys · 12-19-2008, 07:22 AM

Quote:

Originally Posted by Strangler Lewis

Pedant alert:

It's a fun problem, but it works every year. You just would have added 1757 or 1756 last year and 1756 or 1755 the year before. If you do the algebra where x is the first number you choose, you'll see.

I suspected that! Thanks for confirming-I just copied it so I claim no credit for the 2008 thing

Strangler Lewis · 12-19-2008, 07:46 AM

By the way, it also works for 0, 1, 10, 19 and presumably any number

12-19-2008, 06:47 AM	#1
Nephythys Yeah, that's about it- Join Date: Jan 2005 Location: In a state of constant crap to get done Posts: 2,688	Restaurant Math It takes less than a minute. Work this out as you read . Be sure you don't read the bottom until you've worked it out! This is not one of those waste of time things, it's fun. 1. First of all, pick the number of times a week that you would like to go out to eat. (more than once but less than 10) 2. Multiply this number by 2 (just to be bold) 3. Add 5 4. Multiply it by 50 5. If you have already had your birthday this year add 1758... If you haven't, add 1757. 6. Now subtract the four digit year that you were born. You should have a three digit number The first digit of this was your original number. ( I. e., How many times you want to go out to restaurants in a week.) The next two numbers are YOUR AGE ! ------ (Oh YES, it is!) THIS IS THE ONLY YEAR (2008) IT WILL EVER WORK.
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12-19-2008, 06:59 AM	#2
Strangler Lewis Doing The Job Join Date: Aug 2006 Location: In a state Posts: 3,956	Pedant alert: It's a fun problem, but it works every year. You just would have added 1757 or 1756 last year and 1756 or 1755 the year before. If you do the algebra where x is the first number you choose, you'll see. __________________ Live now-pay later. Diner's Club!
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12-19-2008, 07:46 AM	#4
Strangler Lewis Doing The Job Join Date: Aug 2006 Location: In a state Posts: 3,956	By the way, it also works for 0, 1, 10, 19 and presumably any number __________________ Live now-pay later. Diner's Club!
	Submit to Quotes